Vernier Calliper BIEK Practical Volume of Solid Cylinder Capacity of Test Tube
Experiment # 01Vernier Calliper
Object:
To determine (a) Volume of the given solid cylinder (b)
capacity of the given hollow cylinder.
Working
Formula:
Volume: Volume of a solid cylinder is given by:
Where R is the radius of the solid cylinder
and L is the length of the solid cylinder.
Capacity:
Capacity or internal volume of a hollow
cylinder is given by:
Where r is the internal radius of the
hollow cylinder, h is the depth of the hollow cylinder.
Observations:
Least Count:
The smallest division on the main scale,
S = 1mm.
Total number of divisions on vernier
scale N = 10div.
L.C = S/N = 1mm/10 = o.1 mm =
0.01 cm
Zero Error:
Main Scale Reading
MSR
cm
|
Vernier Scale Reading
VSR
div
|
Fractional Part FP =
VSR X L.C
cm
|
Total Reading TR =
MSR + FP
cm
|
Mean Reading
cm
|
|
1
2
3
|
0
0
0
|
0
0
0
|
0
0
0
|
0
0
0
|
0
|
Length, diameter and depth:
Object
|
Quantity
|
SN
|
Main Scale Reading
MSR
cm
|
Vernier Scale Reading
VSR
div
|
Fractional Part FP =
VSR X L.C
cm
|
Total Reading TR =
MSR + FP
cm
|
Mean Reading
cm
|
Solid
Cylinder
|
Length of solid
cylinder (L)
|
1
2
3
|
2.6
2.6
2.6
|
9
8
6
|
0.09
0.08
0.06
|
2.69
2.68
2.66
|
2.68
|
External Diameter (D)
|
1
2
3
|
0.8
0.8
0.8
|
4
5
6
|
0.04
0.05
0.06
|
0.84
0.85
0.86
|
0.85
|
|
Hollow Cylinder
|
Inner Diameter (d)
|
1
2
3
|
1
1
1
|
1
2
3
|
0.01
0.02
0.03
|
1.01
1.02
1.03
|
1.02
|
Depth (h)
|
1
2
3
|
7.2
7.2
7.2
|
1
4
5
|
0.01
0.04
0.05
|
7.21
7.24
7.25
|
7.23
|
Calculation:
Volume of Solid Cylinder (V):
Mean Length, L = 2.69+2.68+2.66/3
L = 2.68 cm
Mean Diameter, D = 0.84+0.85+0.86/3
D = 0.85 cm
Radius, R = D/2 = 0.85/2 = 0.425 cm
V = 3.14 x 0.1806 x 2.68
V = 1.5199 cm
Capacity of the hollow cylinder (C):
Mean Depth, h = 7.21+7.24+7.25/3 = 21.7/3
H = 7.23 cm
Mean inner diameter, d = 1.01+1.02+1.03/3
D = 3.06/3 = 1.02 cm
Inner radius, r = d/2 = 1.02/2 = 0.51 cm
C = 3.14 x 2.601 x 7.233
C = 5.9075 cm x cm x cm
Result:
Volume of the given Solid Cylinder =
1.5199 

Capacity of the given hollow cylinder =
5.9075 

Prepared
by:
Ishtiaq
Ahmed
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